The correct option is B 0.0265 mol
The given reaction is,
Zn+2Fe+4S→Zn[FeS2]2
So, from the balanced reaction,
1 mol of Zn reacts with 2 mol of Fe and 4 mol of S to give 1 mol of Zn[FeS2]2
Finding moles of reactants
2 g of Zn=265 mol of Zn = 0.030 mol of Zn
3 g of Fe=356 mol of Fe = 0.053 mol of Fe
4 g of S = 4/32 moles of S = 0.125 mol of S
We know, 1 mol of Zn reacts with 2 mol of Fe
So, 0.03 mol of Zn will react with 0.06 mol of Fe.
Here we have only 0.053 mol of Fe.
Again, 2 mol of Fe react with 4 mol of S.
So, 0.053 mol of Fe will react with 0.106 mol of S.
Thus, here Fe is the limiting reagent.
From the balanced chemical reaction,
2 mol of Fe react to give 1 mol of Zn[FeS2]2
Thus, 0.053 mol of Fe react to give 0.0265 mol of Zn[FeS2]2.