How many monochlorinated products are possible including stereoisomers?
$C H_{3} - C H_{2} - C H = C H_{2} C l_{2} - - \to h ν$

1

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Solution

The correct option is C $3$

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C H_{2} = C H - C H_{2} - C H_{2} - C H = C H_{2}

N \equiv C - C H_{2} - C H_{2} - C O - N H - C H = C H_{2}

C H_{3} - C H_{3} | C | - C H_{3} C H_{2} - C H_{3} | C H - C H_{3}

B r_{2} / h u - --- \to

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{C H}_{2} = C H - C \equiv C H

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