How many more carbon atoms are present in the amine formed from the reduction of a nitrile, than in the nitrile itself?

1 or 2

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Solution

The correct option is C 0
The $- C N$ group of the nitrile is reduced to $- C H_{2} N H_{2}$ group. $P h - C \equiv N Na(Hg)-ethanol - -------- \to P h - C H_{2} - N H_{2}$
From the reaction it is clear that the number of carbon atoms in reactant as well as in product are same. Thus there is no more extra carbon in product.
Hence, the correct answer is option (c).

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