Question

How many multiple of $9$ lie between $10$ and $300$?

Answer 1

Given multiple of 9 between 10 & 300

First number

a=18

and common difference = 9.

Total number between 10 & 300 = 300 - remainder of $\left(\frac{300}{9}\right)$

Last term = 300-3 =297

Given sequences is 18,27,......297.

Total multiple of 9 between 10 & 300.

297=18+(n-1)9

297-18+9=9n

9n=297-9=288

[n=32]

$\therefore$ Total term are 32 whose are multiple of 9.