wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

How many natural number solutions are possible for equation below ?
x + y +z + w = 20

A
23C3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
22C2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
19C3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 19C3
In this case partion rule is applicable, such that each of x, y, z and w should get at least one thing.

hence no. of ways
=201C41=19C3

Hence option (c)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Permutations & Combinations
OTHER
Watch in App
Join BYJU'S Learning Program
CrossIcon