Question

How many natural numbers are present in between the 7th and the 8th perfect square number?

• A. $1\times 7$
• B. $2\times 7$
• C. $1\times 8$
• D. $2\times 8$

Answer 1

The correct option is B $2\times 7$

7th perfect square= 49
8th perfect square= 64
There are $2n$ natural numbers between $n^2$ and $(n+1{)}^2$. So, numbers present are $2\times 7=14$

The numbers present in between 49 and 64 are:
{50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63}