1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Mathematics
Combination of n Different Things Taken One or More at a Time
How many natu...
Question
How many natural numbers are there from
1
to
1000
which have none of their digits
repeated.
Open in App
Solution
From
1
to
1000
we have
1 digit, 2 digit and 3 digit numbers
1 digit
→
9
ways
2 digit
¯
¯¯¯¯¯
¯
↓
9
¯
¯
¯
9
cant take 0
9
×
9
=
81
ways
2nd digit can't take 1st digit number
similarly
3 digit
¯
¯
¯
9
¯
¯
¯
9
¯
¯
¯
8
=
9
×
9
×
8
=
648
=
648
+
81
+
9
=
738
ways
Suggest Corrections
1
Similar questions
Q.
Find the number of natural numbers from
1
to
1000
having none of their digits repeated.
Q.
How many natural numbers less than 1000 can be formed from the digits 0, 1, 2, 3, 4, 5 when a digit may be repeated any number of times?
Q.
How many numbers are there between
99
and
1000
which have exactly one of their digits as
7
?
Q.
Number of odd integers between
1000
and
8000
which have none of their digits repeated, is
Q.
Find the number of odd integers between 1000 and 8000 which have none of their digits repeated.
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Nuclear Energy
MATHEMATICS
Watch in App
Explore more
Combination of n Different Things Taken One or More at a Time
Standard XII Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app