How many natural numbers are there from $87$ to $97$ ? What fraction of them are prime numbers?

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Solution

The total number from $87$ to $97$ $=$ $87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97$
The prime number from $87$ to $97$ $= 89, 97$
Required Fraction $= \frac{2}{11}$
Hence, The required fraction is $\frac{2}{11}$ .

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