Question

How many neutrons are contained in A formed by the reaction?
${}_4^{9}Be(\alpha ,n)⟶A$

• A. 6
• B. 4
• C. 5
• D. 1

Answer 1

The correct option is D 1

In the following reaction:

${}_2^{4}He{+}_4^{9}Be{\to }_6^{12}C{+}_0^{1}n$ or ${}_4^{9}Be(\alpha ,n{)}_6^{12}C$

The number of neutrons formed is $1$.