How many neutrons are present in the nucleus of Ra

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226

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140

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138

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Solution

Number of neutrons in $_{88} R a^{226} = 226 - 88 = 138$

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How many neutrons are present in the nucleus of Ra

Number of neutrons in 88Ra226=226−88=138

Number of neutrons in $_{88} R a^{226} = 226 - 88 = 138$