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Question

How many nodal planes are there in atomic orbitals corresponding to the principal quantum number n=3?

A
9
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B
11
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C
13
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D
15
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Solution

The correct option is B 11
For n=3, values of l corresponds to (0 to 2). The corresponding orbitals are as follows:
3 sorbital 3s
3 porbital 3px, 3py, 3pz
3 dorbital 3dxy, 3dyz, 3dzx, 3dx2y2, 3dz2
We know that,
's' orbital has no nodal plane.
Each of px, py, pz has one nodal plane, which means a total of three nodal planes.
Each of dxy, dyz, dzx, dx2y2 has two nodal planes each and dz2 has no nodal plane which means a total of eight nodal planes.

Hence, for n=3, there are a total of 11 nodal planes.

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