Question

How many Normal Cheese pizzas were required to be delivered to Party?

• A. 104
• B. 84
• C. 16
• D. 196

Answer 1

The correct option is C 16

Given, Number of pizzas to be delivered to Party $3=0.7\times 800=560$
Number of pizzas to be delivered to Party 2 = Number of pizzas to be delivered to Party $1=\frac{(800-560)}{2}=120$
Refer to the table below:
$\begin{array}{ccc}Party& ThinCrust\left(T\right)& NormalCheese\left(NC\right)\\ 1& 0.6\times 120=72& 416-36-364=16\\ 2& 0.55\times 120=66& 0.3\times 120=36\\ 3& 300-72-66=162& 0.65\times 560=364\\ Total& 0.375\times 800=300& 0.52\times 800=416\end{array}$
As can be seen in the table, number of Normal Cheese (NC) pizzas to be delivered to Party 1 = 16.