How many number of electrons are present in a particle which carries a charge of 5.5×10−16C?

3432

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1560

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8240

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2432

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Solution

The correct option is A 3432
The charge carried by one electron =1.6022×10⁻¹⁹C
Number of electrons × charge of 1 electron= 5.5×10⁻¹⁶C
n×1.6022×10−19=5.5×10⁻¹⁶
n= $\frac{5.5 \times 10^{- 16} C}{1.6022 \times 10^{- 19} C}$
n=3432 electrons
Option A is correct

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How many number of electrons are present in a particle which carries a charge of 5.5×10−16C?

The correct option is A 3432The charge carried by one electron =1.6022×10−19CNumber of electrons × charge of 1 electron= 5.5×10−16C n×1.6022×10−19=5.5×10−16n=5.5×10-16C1.6022×10-19Cn=3432 electronsOption A is correct

The correct option is A 3432
The charge carried by one electron =1.6022×10⁻¹⁹C
Number of electrons × charge of 1 electron= 5.5×10⁻¹⁶C
n×1.6022×10−19=5.5×10⁻¹⁶
n= $\frac{5.5 \times 10^{- 16} C}{1.6022 \times 10^{- 19} C}$
n=3432 electrons
Option A is correct