How many number of electrons lost or gained during the redox change ?

$3 N_{2} H_{4} + 2 {B r O}_{3}^{-} ⟶ 3 N_{2} + 2 B r^{-} + 6 H_{2} O$

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Solution

The correct option is C 12
The given reaction is -

$3 N_{2} H_{4} + 2 {B r O}_{3}^{-} ⟶ 3 N_{2} + 2 B r^{-} + 6 H_{2} O$
-2 +5 0 -1
Electron gain by each Br is 6. Therefore the total number of electrons gained in this reaction is 12.

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Similar questions

3 N_{2} H_{4} + 2 {B r O}_{3}^{-} ⟶ 3 N_{2} + 2 B r^{-} + 6 H_{2} O

3 N_{2} H_{4} + 2 B r O_{3}^{-} \to 3 N_{2} + 2 B r^{-} + 6 H_{2} O

3 N_{2} H_{4} + 2 {B r O}_{3}^{-} \to 3 N_{2} + 2 B r^{-} + 6 H_{2} O

3 N_{2} H_{4} + 2 B r O_{3}^{-} \to 3 N_{2} + 2 B r^{-} + 6 H_{2} O

A l C l_{3} + 3 K \to A l + 3 K C l

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