Question

How many number of protons present in 32g of SO2

Answer 1

• Divide the given mass by the molecular weight of SO₂ to get number of moles (n), then multiply moles by Avogadro's number to get number of molecules (N).
  
  Atomic weights:
  
  S = 32.07 g/mole
  O = 16.00 g/mole
  
  Molecular weight:
  
  SO₂ = 32 + 2(16.00) = 64 g/mole
  
  n = (32 g) / (64 g/mole) = 0.5 moles
  
  N = nA = (0.5 moles) (6.02 x 10²³molecules/mole) = 3.01 x 10²³molecules
  
  There are about 3.01 x 10²³molecules of SO₂ in 32 g of $S{O}_2$

• The number of protons in Sulphur is 16 and the number of protons of oxygen is 8 since the atomic number of sulphur and oxygen is 16 and 8 respectively

• ​ The total number of protons in one molecule of $S{O}_2$ are $16+(2\times 8)=32protons$

• So one molecule of $S{O}_2$ contains 32 protons.

Hence the total number of protons in $3.01\times {10}^{23}$ molecules is$32\times 3.01\times {10}^{23}=9.632\times {10}^{24}protons$