Question

How many numbers between 2000 and 3000 can be formed with the digits 0, 1, 2, 3, 4, 5, 6, 7 (repetition of digits not allowed)?

• A. 42
• B. 210
• C. 336
• D. 440

Answer 1

The correct option is B 210

Number between 2000 and 3000 are four digit numbers in which 2 is the first digit
So, 2 must be taken in box
$d_1$
Now rest box can be filled in
${}^7{P}_{3}ways$

$\Rightarrow \frac{7!}{(7-3)!}=210ways$