How many numbers between 3000 and 4000 can be formed from the digits 3,4,5,6,7 and 8 with no digits being repeated in any number?
A
20
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B
15
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C
60
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D
120
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Solution
The correct option is B60 The first place filled with 3−1 way Second place −5ways Third place −4 ways Fourth place −3 ways Total numbers =1×5×4×3=60 ways Hence, option 'C' is correct.