How many numbers can be formed from 1, 2, 3, 4, 5 (without repeating), where the digit at the unit’s place must be greater than that in the ten’s place?(CAT 1998)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2×4!

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 60
Case 1 : units place= 1 (0 possibilities)

Case 2 : units place = 2 (tens place=1 possibility (2) and 3! Arrangements for the remaining places) = 1 $\times$ 3!

Case 3 : units place = 3 (tens place=2 possibilities (1,2) and 3! Arrangements for the remaining places) = 2 $\times$ 3!

Case 4 : units place = 4 (tens place=3 possibilities (1,2,3) and 3! Arrangements for the remaining places) = 3 $\times$ 3!

Case 5 : units place = 5 (tens place=4 possibilities (1,2,3,4) and 3! Arrangements for the remaining places) = 4 $\times$ 3!

Total = 60

Suggest Corrections

Similar questions

Q. How many numbers can be formed from 1, 2, 3, 4, 5(without repeating), where the digit at the unit’s place must be greater than that in the ten’s place?(CAT 1998)

Q. In two-digit numbers, how many times does the digit 5 occur in
(i) the ten's place (ii) the unit's place?

Q. How many numbers greater than

23, 000

can be formed from the digits

1, 2, 3, 5,

and

6

without repeating any digit?

Q. How many numbers greater than 24000 can be formed by using digits 1, 2, 3, 4, 5 when no digit is repeated

In a two-digit number, if two is added to the digit in ten's place, the number formed will have ten's place digit which is 0.6 times the original one and unit's digit which is four times more than the initial digit in unit's place. The difference between the digits in ten's place and that in unit's place is

Join BYJU'S Learning Program