Question

How many numbers divisible by 5 and lying between 3000 and 4000 can be formed from the digits 1, 2, 3, 4, 5, 6 (repetition is not allowed)

• A. ${}^6{P}_2$
• B. ${}^5{P}_2$
• C. ${}^4{P}_2$
• D. ${}^6{P}_3$

Answer 1

The correct option is C ${}^4{P}_2$

To be divisible by 5, the digit 5 must be at unit place, so now to be between 3000 and 4000, 3 must be at thousand place. Hence the required number of ways ${=}^4{P}_2$.