Question

How many numbers greater than a million can be formed with the digits 5, 5, 2, 2, 1, 7, 0?

• A. 980
• B. 1080
• C. 920
• D. 1200

Answer 1

The correct option is B 1080

$\begin{array}{ccccccc}6& 6& 5& 4& 3& 2& 1\end{array}$
Since left most place can assume only non -zero digit and rest can assume all the given digits.
Therefore the number of numbers = 6.(6!)
But since 5 occurs 2 times and 2 occurs 2 times
Hence the required number of numbers $=\frac{6.(6!)}{2!.2!}$ = 1080