How many numbers lie between squares of the following numbers: $10$ and $11$ ?

22

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20

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21

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23

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Solution

The correct option is A $20$
We have,
$10^{2} = 100$
and $11^{2} = 121$
Now, $121 - 100 = 21$
So, there are $21 - 1 = 20$ numbers lying between the square of the numbers $10$ and $11$ .

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