Question

How many numbers lie between squares of the following numbers: $14$ and $26$?

• A. $479$
• B. $478$
• C. $481$
• D. $480$

Answer 1

The correct option is A $479$

${14}^2=196$
${26}^2=676$
Now, $676-196=480$
So, there are $480-1=479$ numbers lying between the square of the numbers $14$ and $26$.