Question

How many numbers lie between squares of the numbers $99$ and $100$

Answer 1

Solve for the numbers lie between the squares of the given number

The given numbers are $99$ and $100$

The number of numbers between $n^2$ and${\left(n+1\right)}^2$ are $2n$

Here we have, $n=99$ and $n+1=100$

Hence, the numbers lying between ${99}^2$ and ${100}^2$ are given as

$2n=2\times 99$

$=198$

Hence there are $198$ numbers between the squares of $99$ and $100$