Question

How many numbers lies between $100$ and $400$, which are exactly divisible by $11$.

• A. 25
• B. 26
• C. 27
• D. 28

Answer 1

The correct option is C 27

Have many numbers lies between $100$ AND $400$ which are exactly divisible by $11.$

$=>99+11=110$ [If we divide $100$ by $11$ we will get $99$ with remainder $1$]

$1^{st}$ term would be$=110$

Last term$=(400-4)=396$ [If we divide $400$ by $11$ we will get 36 with remainder $4$]

$t_n=110+(n-1)11=396$

$r,110+11n-11=396$

$=>11n=396+11-110=297$

$=>n=\frac{297}{11}=27$