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Question
How many numbers (N) can we have, such that 100<N<1000 with the sum of the digits of these numbers as 10?
How many numbers (N) can we have, such that 100<N<1000 with the sum of the digits of these numbers as 10?
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Solution
The correct option is A 55
Use the concept of grouping, for a three digit number ABC
A+B+C = 10, A >1
It changes to A + B + C = 9
Number of possible solutions = 11C2 = 55
Use the concept of grouping, for a three digit number ABC
A+B+C = 10, A >1
It changes to A + B + C = 9
Number of possible solutions = 11C2 = 55
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