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Quantitative Aptitude

A+B+C=N (N Fixed), with Lower Limit

How many numb...

Question

How many numbers (N) can we have, such that 100<N<1000 with the sum of the digits of these numbers as 10?

A

55

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B

66

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C

78

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D

27

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E

52

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Solution

The correct option is A 55
Use the concept of grouping, for a three digit number ABC

A+B+C = 10, A >1

It changes to A + B + C = 9

Number of possible solutions = $^{11} C_{2} = 55$

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