Question

How many numbers of $6$ digits can be formed from the digits $1,1,2,2,3,3$?

• A. 30
• B. 60
• C. 90
• D. 120

Answer 1

The correct option is C 90

The total number of arrangements of the six digits given can be $\frac{6!}{2!2!2!}$ since 1,2,3, are repeted twice.

Thus, $\frac{6!}{2!2!2!}=90$ possible six digit numbers.