How many numbers with not more than three digits can be formed using only the digits 1 through 7 with no digit used more than once in a given number?
A
259
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
249
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
257
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
252
No worries! We‘ve got your back. Try BYJU‘S free classes today!
E
269
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A259 Numbers can be with 1 digit, 2 digit and 3 digit are formed by 1,2,3,4,5,6,7 Therefore, required numbers are 7P1+7P2+7P3=259.