How many of following elements will liberate $H_{2}$ gas when treated with dil $H N O_{3}$ ?
Mg, Zn, Sn, Pb

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Solution

The correct option is A 1
Of the given options, only the reaction between magnesium and nitric acid liberates hydrogen gas.

$M g + 2 H N O_{3} \to M g (N O_{3})_{2} + H_{2}$
$3 Z n + 8 H N O_{3} \to 3 Z n (N O_{3})_{2} + 2 N O + 4 H_{2} O$
$4 S n + 10 H N O_{3} \to 4 S n (N O_{3})_{2} + N H_{4} N O_{3} + 3 H_{2} O$
$P b + 4 H N O_{3} \to P b (N O_{3})_{2} + 2 H_{2} O + 2 N O_{2}$

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Similar questions

Q. Generally, when metals are treated with mineral acids, hydrogen gas is liberated. But, when metals (except

M n

and

M g

) are treated with

H N O_{3}

, hydrogen is not liberated. Why?

Question 40
Generally, when metals are treated with mineral acids, hydrogen gas is liberated but when metals (except Mn and Mg) are treated with ${HNO}_{3}$ , hydrogen is not liberated. Why?

Which of the following is not obtained when Zn is treated with dil. $H N O_{3}$ ?

Which of the following will liberate H $_{2}$ when reacting with NaOH?

Z n

gives

H_{2}

gas with

H_{2} S O_{4}

and

H C l

but not with

H N O_{3}

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How many of following elements will liberate H2 gas when treated with dil HNO3?Mg, Zn, Sn, Pb

The correct option is A 1Of the given options, only the reaction between magnesium and nitric acid liberates hydrogen gas.Mg+2HNO3→Mg(NO3)2+H23Zn+8HNO3→3Zn(NO3)2+2NO+4H2O4Sn+10HNO3→4Sn(NO3)2+NH4NO3+3H2OPb+4HNO3→Pb(NO3)2+2H2O+2NO2

How many of following elements will liberate $H_{2}$ gas when treated with dil $H N O_{3}$ ?
Mg, Zn, Sn, Pb