How many of the following ions have spin magnetic moment more than four B.M.?
$T i^{3 +}, C u^{+}, N i^{2 +}, F e^{3 +}, M n^{2 +}, C o^{2 +}$

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Solution

The spin magnetic moment can be calculated by $m_{s} = \sqrt{n (n + 2)}$ , where $n$ is the number of unpaired electrons.

$T i^{3 +}$ $3 d^{1}$ 1 $\sqrt{2}$

$C u^{+}$ $3 d^{10}$ 0 0

$N i^{2 +}$ $3 d^{8}$ 2 $\sqrt{8}$

$F e^{3 +}$ $3 d^{5}$ 5 $\sqrt{35}$

$M n^{2 +}$ $3 d^{5}$ 5 $\sqrt{35}$

$C o^{2 +}$ $3 d^{7}$ 3 $\sqrt{15}$

So the number ions having spin magnetic moment more than four B.M are 2

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