Question

How many of the following reaction(s) is/are correct?
$\left(i\right)BaC{l}_2+AcOH+K_{2}Cr{O}_4\to \text{Yellow ppt}$
$\left(ii\right)BaC{O}_3\left(s\right)+AcOH+K_2{C}_2{O}_4\to \text{White ppt}$
$\left(iii\right)BaC{O}_3\left(s\right)+AcOH+K_{2}Cr{O}_4\to \text{No ppt}$
$\left(iv\right)SrC{O}_3\left(s\right)+AcOH+K_{2}Cr{O}_4\to \text{No ppt}$

• A. 2.00
• B. 2.0
• C. 2

Answer 1

Answer: (A), (B), (C)

$\left(a\right)B{a}^{+2}$ ions produce yellow ppt with $Cr{O}_4^{2-}$, which is not soluble in $C{H}_{3}COOH$.
$\left(b\right)BaC{O}_3$ dissolves in $C{H}_{3}COOH$ and produces $B{a}^{+2}$ ions which gives yellow ppt. with $Cr{O}_4^{2-}$ which is insoluble in $C{H}_{3}COOH$
$\left(c\right)SrC{O}_3$ is soluble in $C{H}_{3}COOH$ and produces $S{r}^{+2}$ which reacts with $K_{2}Cr{O}_4$ to furnish a light yellow $SrCr{O}_4$, which is readily soluble in acid. Hence no ppt is observed in acetic acid.