The correct option is
B 6Given Numbers are
17871,1007453,4343143,990039,125144,888888,6412Divisibilty test of 11 is as follows:
Take sum of alternate digits from left and then subtract it from the sum of numbers present at even places from the left. and then check if the result is divisible by 11.
Using this divisibility test:
17871 → (1+8+1) − (7+7) → −4
1007453 → (1+0+4+3) − (0+7+5) → −4
4343143 → (4+4+1+3) − (3+3+4) → 2
990039→ (9+0+3) − (9+0+9) → −6
125144 → (1+5+4) − (2+1+4) → 3
888888 → (8+8+8) − (8+8+8) → 0
6412 → (6+1) − (4+2) → 1
By divisibility test, only 0 is divisible by 11, so is 888888