Question

How many $O{H}^{-}$ are present in 1 ml of a solution, whose $pH$= 13

• A. $6.02\times {10}^{19}$
• B. $6.02\times {10}^{24}$
• C. $6.02\times {10}^{-13}$
• D. $6.02\times {10}^{-19}$

Answer 1

The correct option is A $6.02\times {10}^{19}$

$pH=13:pOH=1;\left[O{H}^{-}\right]=0.1M$
1000 ml contains 0.1 moles i.e, $6.02\times {10}^{22}O{H}^{-}$ions
1 ml contains . . . .. . . ?
$\frac{1\times 6.02\times {10}^{22}}{{10}^3}=6.02\times {10}^{19}$