How many optically inactive isomers are present in $C H_{3} - C H (O H) - C H (O H) - C O O H$ ?

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 0
The given compounds have no plane of symmetry and there is no line of symmetry and point of symmetry,

Thus it is an optically inactive compound. Hence, in the given compound, there are no optically active isomers found.

So, the correct option is $A$

Suggest Corrections

Similar questions

H O O C - C H (O H) - C H (O H) - C H (O H) - C O O H

H O O C - C H (O H) - C H (O H) - C O O H

H O O C - C H (O H) - C H (O H) - C H (O H) - C O O H

H O O C - C H O H - C H O H - C H O H - C H O H - C H O H - C O O H

The total number of optically active isomers for $C H_{2} O H (C H O H)_{3} C H O$ are:

Join BYJU'S Learning Program