The correct option is
C 16
For 4th energy level, n=4 and possible values of l and ml are:
l=0,1,2,3
ml=0 for l=0; total ml values =1
ml=−1,0,1 for l=1; total ml values =3
ml=−2,−1,0,1,2 for l=2; total ml values =5
ml=−3,−2,−1,0,1,2,3 for l=3; total ml values =7
Total number of orbitals = total values of ml
For n=4,
∴1+3+5+7=16 orbitals present in 4th energy level.
Hence, option C is correct.