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Question

How many ordered pairs of (m, n) integers satisfy m12=12n?

A
30
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B
15
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C
12
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D
10
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Solution

The correct option is B 15
m×n=144
144 can be written in multiplication of two integers in the following ways:

1×144=2×72=3×48=4×36=6×24=8×18=9×16=12×12

For all the factors except (12,12) there would be 14 ordered pairs.
Adding one more, yields 15 possibilities

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