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Question

How many oxygen atoms are present in 50g of CaCO3?



Your Answer
A
3.011 × 1023
Your Answer
B
6.022 × 1023
Correct Answer
C
9.033 × 1023
Your Answer
D
12.044 × 1023

Solution

The correct option is B 9.033 × 1023

Molecular Mass of CaCO3  = (40 × 1) + (12 × 1) + (16 × 3) = 100g
100g of CaCO3  = 1 mole of CaCO3 
50g of CaCO3  = 0.5 mole of CaCO3
1 mole of CaCO3=3×6.022×1023atoms of Oxygen0.5 mole of CaCO3=32×6.022×1023atoms of Oxygen=9.033×1023 atoms of Oxygen

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