How many paint tins having speed capacity of $100 c m^{2}$ will be required to paint external surface of box having dimensions $80 c m \times 50 c m \times 25 c m$ .

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Solution

Surface area of cuboid $= 2 (l b + b h + h l)$
( $l =$ length, $b =$ breadth, $h =$ height)
$= 2 (4000 + 1250 + 2000)$
$= 2 (5250 + 2000) = 2 (7250) = 14500 c m^{2}$
$\Rightarrow$ Number of point this required $= \frac{14500}{100} = 145$ .

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How many paint tins having speed capacity of 100 cm2 will be required to paint external surface of box having dimensions 80 cm×50 cm×25 cm.

Surface area of cuboid =2(lb+bh+hl)(l= length, b= breadth, h= height)=2(4000+1250+2000)=2(5250+2000)=2(7250)=14500cm2⇒ Number of point this required =14500100=145.

How many paint tins having speed capacity of $100 c m^{2}$ will be required to paint external surface of box having dimensions $80 c m \times 50 c m \times 25 c m$ .

Surface area of cuboid $= 2 (l b + b h + h l)$
( $l =$ length, $b =$ breadth, $h =$ height)
$= 2 (4000 + 1250 + 2000)$
$= 2 (5250 + 2000) = 2 (7250) = 14500 c m^{2}$
$\Rightarrow$ Number of point this required $= \frac{14500}{100} = 145$ .