How many pairs of co-prime natural numbers a and b exist such that a + b = 510?
60
120
64
128
510=2×3×5×17. Use the concept of Euler's theorem: 510(1−12)(1−13)(1−15)(1−117)=128 Number of pairs=1282=64.
In first 1000 natural numbers, how many numbers exists such that when divided by 11 leaves a remainder of 8?