How many pairs of integers are there- satisfying the equation x 2- y 2-25 -A- 3 pairsB- 4 pairsC- 2 pairsD- 8 pairs

The correct option is B 4 pairs When x = 0, y = 5, x^2 + y^2 = 0^2 + 5^2 = 25 When x = 0, y = 5, x^2 + y^2 = 0^2 + ( 5)^2 = 25 When x = 5, y = 0, x^2 + y^2 = ...

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Standard VIII

Mathematics

Addition of Negative Numbers

How many pair...

Question

How many pairs of integers are there, satisfying the equation $x^{2} + y^{2} = 25 ?$

3 pairs

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8 pairs

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4 pairs

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2 pairs

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Solution

The correct option is C
4 pairs

When x = 0, y = 5, $x^{2} + y^{2} = 0^{2} + 5^{2} = 25$

When x = 0, y = -5, $x^{2} + y^{2} = 0^{2} + (- 5)^{2} = 25$

When x = 5, y = 0, $x^{2} + y^{2} = 5^{2} + 0^{2} = 25$

When x = -5, y = 0, $x^{2} + y^{2} = (- 5)^{2} + 0^{2} = 25$

Hence, 4 pairs [(0,5),(0, -5), (5,0), (-5,0)] of integers are possible satisfying the equation $x^{2} + y^{2} = 25$

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How many pairs of integers are there, satisfying the equation x2+y2=25?

The correct option is C 4 pairs When x = 0, y = 5, x2+y2=02+52=25 When x = 0, y = -5, x2+y2=02+(−5)2=25 When x = 5, y = 0, x2+y2=52+02=25 When x = -5, y = 0, x2+y2=(−5)2+02=25 Hence, 4 pairs [(0,5),(0, -5), (5,0), (-5,0)] of integers are possible satisfying the equation x2+y2=25

How many pairs of integers are there, satisfying the equation $x^{2} + y^{2} = 25 ?$