How many pairs of the below following species are isoelectronic?
[ $N_{2} O, C O_{2}, {C N}_{2}^{2 -}, N_{3}^{-}, N H_{2} O H, N_{3} H$ ]

Open in App

Solution

Four species are isoelectronic.
The species, along with the number of electrons are given below.
$N_{2} O$ 44 electrons
$C O_{2}$ 44 electrons
$C N_{2}^{2 -}$ 42 electrons
$N_{3}^{-}$ 43 electrons
$N H_{2} O H$ 33 electrons
$N_{3} H$ 43 electrons.
Thus $N_{2} O$ and $C O_{2}$ are isoelectronic species with 44 electrons each.
Also, $N_{3}^{-}$ and $N_{3} H$ are isoelectronic with 43 electrons each.

Therefore 2 pairs are isoelectronic.

Suggest Corrections

Similar questions

N_{2} O

C O_{2}

{N_{3}}^{-}

N - O - N

N_{2} O

C O_{2}

C O_{2}

C H_{4}

N_{2} O

C O_{2}

Join BYJU'S Learning Program