Question

How many permutations can be made with the letters of the word ${}^{\prime }MEADOW{S}^{\prime }$ such that the vowels occupy even places?

• A. $720$
• B. $144$
• C. $120$
• D. $36$

Answer 1

The correct option is B $144$

$MEADOWS$

Consonant$=4$

Vowels$=3$

Places for vowels $=3!$ possibilities

Remaining consonants can be arranged in $4!$ Possibilities

Total arrangements

$3!\times 4!=6\times 24=144$

Hence the correct answer is $144$