How many persons can be accommodated in a dining hall of dimensions $(20 m \times 15 m \times 4.5 m)$ , assuming that each person requires $5 m^{3}$ of air?

(a) 250 (b) 270 (c) 320 (d)300

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Solution

The volume of hall = $(20 m \times 15 m \times 4.5 m)$ = 1350 $m^{3}$

Given,

Each person requires $5 m^{3}$ volume of air.

Number of persons can be accommodated in a dining hall $= \frac{v o l u m e o f h a l l}{v o l u m e r e q u i r e d b y e a c h p e r s o n}$ = $\frac{1350}{5}$ = 270

$∴$ 270 persons can be accommodated in a dining hall. So, option (b) is correct.

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$How many persons can be accoummodated in a dining hall of dimensions (20 m \times 16 m \times 4.5 m), assuming thatg each person requires 5 cubic metres of air ?$

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How many persons can be accommodated in a dining hall of dimensions (20m×15m×4.5m), assuming that each person requires 5m3 of air? (a) 250 (b) 270 (c) 320 (d)300

The volume of hall = (20m×15m×4.5m) = 1350 m3 Given, Each person requires 5m3 volume of air. Number of persons can be accommodated in a dining hall =volumeofhallvolumerequiredbyeachperson = 13505 = 270 ∴ 270 persons can be accommodated in a dining hall. So, option (b) is correct.

How many persons can be accommodated in a dining hall of dimensions $(20 m \times 15 m \times 4.5 m)$ , assuming that each person requires $5 m^{3}$ of air?

(a) 250 (b) 270 (c) 320 (d)300