Sol:
Given that hall of Length = 16 m, Breadth = 12.5 m, Height = 4.5 m.
∴Volume of the hall = length × breadth × height
= 16 × 12.5 × 4.5
= 900 m3
Volume occupied by 1 man = 3.6 m3
Therefore, number of men that can be accommodated = 900 / 3.6 = 250.