How many PGAL are produced by glycolysis of 3 molecules of glucose? How many ATP are released by respiration of these PGAL till formation of $C O_{2}$ and $H_{2} O$ ?

4 PGAL-80 ATP

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6 PGAL-160 ATP

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4 PGAL-40 ATP

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6 PGAL-120 ATP

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Solution

The correct option is D 6 PGAL-120 ATP
Glycolysis of one molecule of glucose produces 2 PGAL, thus three molecules of glucose will produce 6 PGAL.
During glycolysis, two ATP molecules are utilized for the conversion of glucose to fructose 1- 6, bis phosphate.
When two molecules of PGAL are completely oxidized during aerobic respiration, a total of 40 ATP molecules is released.
Therefore 3*40 = 120 ATP molecules are released upon complete oxidation of 6 molecules of PGAL.

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