How many PGAL are produced by glycolysis of 3 molecules of glucose? How many ATP are released by respiration of these PGAL till formation of $C O_{2}$ and $H_{2} O$ ?

4 PGAL-80 ATP

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6 PGAL-160 ATP

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4 PGAL-40 ATP

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6 PGAL-120 ATP

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Solution

The correct option is D 6 PGAL-120 ATP
Glycolysis of one molecule of glucose produces 2 PGAL, thus three molecules of glucose will produce 6 PGAL.
Respiration of 1 molecule of glucose or 2 PGAL produces 38 ATP molecules, therefore 3 molecule of glucose, i will produce $38 \times 3 = 114$ ATP molecules. Thus, out of the given options, 120 ATP is the nearest correct answer.

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