How many photons are emitted by 25 watt bulb per second, which emits light of 400 nm?

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Solution

E=hC/λ

=(6.63x10^-34) $\times$ $\frac{3 \times 10^{8}}{400 \times 10^{- 9}}$

also,

Power= $\frac{E}{t}$

$25 = \frac{4.97 \times 10^{- 9}}{t}$

number of photons= $\frac{1}{t}$

=5.03001 $\times$ 10⁹

^{HENCE PROVED}

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How many photons are emitted by 25 watt bulb per second, which emits light of 400 nm?

E=hC/λ =(6.63x10-34)×3×108400×10-9 also, Power=Et 25=4.97 ×10-9t number of photons=1t =5.03001×109 HENCE PROVED

E=hC/λ

=(6.63x10^-34) $\times$ $\frac{3 \times 10^{8}}{400 \times 10^{- 9}}$

also,

Power= $\frac{E}{t}$

$25 = \frac{4.97 \times 10^{- 9}}{t}$

number of photons= $\frac{1}{t}$

=5.03001 $\times$ 10⁹

^{HENCE PROVED}