Question

How many pi bonds are present in the molecule of ${\mathrm{CH}}_3-\mathrm{CH}=\mathrm{CH}-\mathrm{C}\equiv \mathrm{CH}$?

• A. 2 bonds
• B. 3 bonds
• C. 8 bonds
• D. 9 bonds

Answer 1

The correct option is B

3 bonds

The explanation for the correct answer:

Option (B) 3 bonds

• pi($\mathrm{\pi }$) bonds are formed due to lateral overlapping while sigma($\mathrm{\sigma }$) bonds are formed by head-on overlapping.
• pi bonds are formed by the mutual sharing of electrons between atoms of the same or different elements.
• It is formed between nodal planes with zero electron density.
• In any compound, if there are two bonds between any two atoms then one of them is pi($\mathrm{\pi }$) bond and if there is a triple bond then there are two pi($\mathrm{\pi }$)-bonds.
• In ${\mathrm{CH}}_3-\mathrm{CH}=\mathrm{CH}-\mathrm{C}\equiv \mathrm{CH}$, there is one double and one triple bond, that is there are three pi($\mathrm{\pi }$)-bonds.

Therefore, the correct answer is option B.