How many pieces of plywood, each 0.35 cm thick, are required to make a pile 1.89 m high?

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Solution

Thickness of the pile of plywood pieces = 1.89 m = 189 cm
Thickness of one piece of plywood = 0.35 cm
∴ Required number of plywood pieces = $(\frac{189}{0.35}) = (\frac{189 \times 100}{0.35 \times 100}) = (\frac{18900}{35}) = 540$

Hence, 540 pieces of plywood are required to make a pile of height 1.89 m.

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How many pieces of plywood, each 0.35 cm thick, are required to make a pile 1.89 m high?

Thickness of the pile of plywood pieces = 1.89 m = 189 cm Thickness of one piece of plywood = 0.35 cm ∴ Required number of plywood pieces = 1890.35=189×1000.35×100=1890035=540 Hence, 540 pieces of plywood are required to make a pile of height 1.89 m.