How many pieces of plywood, each of 0.45 cm thick, are required to make a pile 2.43 m high?

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Solution

Thickness of the pile of plywoods = 2.43 m = 2.43 $\times$ 100 cm = 243 cm
Thickness of one piece of plywood = 0.45 cm
∴ Required number of pieces of plywood = $\frac{243}{0.45} = \frac{243 \times 100}{0.45 \times 100} = \frac{24300}{45} = 540$

Hence, the required number of pieces of plywood is 540.

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How many pieces of plywood, each of 0.45 cm thick, are required to make a pile 2.43 m high?

Thickness of the pile of plywoods = 2.43 m = 2.43 × 100 cm = 243 cm Thickness of one piece of plywood = 0.45 cm ∴ Required number of pieces of plywood = 2430.45=243×1000.45×100=2430045=540 Hence, the required number of pieces of plywood is 540.